The products formed in the following reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of anisole $(C_6H_5OCH_3)$ with $HI$ involves the cleavage of the $C-O$ bond.In alkyl aryl ethers,the $O-CH_3$ bond is weaker than th

Vedclass · Accepted Answer

$C_6H_5-OH$ and $CH_3-I$

Vedclass · Answer

(B) The reaction of anisole $(C_6H_5OCH_3)$ with $HI$ involves the cleavage of the $C-O$ bond.In alkyl aryl ethers,the $O-CH_3$ bond is weaker than the $O-C_6H_5$ bond because the $O-C_6H_5$ bond has partial double bond character due to resonance.Therefore,the $HI$ attacks the methyl group,leading to the formation of phenol $(C_6H_5OH)$ and methyl iodide $(CH_3I)$.The reaction is: $C_6H_5OCH_3 + HI \xrightarrow{	ext{heat}} C_6H_5OH + CH_3I$.

The products formed in the following reaction are $C_6H_5-OCH_3 + HI \xrightarrow{\text{heat}}$

Similar Questions

Identify the missing product in the following reaction: $C_6H_5ONa + CH_3CH_2Br \rightarrow (?)$

What product is formed when anisole reacts with concentrated $HNO_3$ and concentrated $H_2SO_4$?

In the given reaction
$C_6H_5 - O - CH_2 - CH_3 \xrightarrow{\text{Excess } HI / \Delta} [X] + [Y]$
$[X]$ and $[Y]$ will respectively be

$CH_3-C(CH_3)_2-OCH_3 \xrightarrow{\text{Conc. } HI}$ The type of reaction in the above reaction is:

The major product in the following conversion is

Vedclass Test Series

Exam Paper Generator

Online Exam Module